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211133422223081 is a prime number
BaseRepresentation
bin110000000000011001010100…
…101000011011111011101001
31000200120011021012201221000122
4300000121110220123323221
5210133202222042114311
62025013204414213025
762320613011631231
oct6000312450337351
91020504235657018
10211133422223081
11613011aa676226
121b81b0a3ab4175
1390a6a47591817
143a1ccaad78cc1
1519620e8c540db
hexc00654a1bee9

211133422223081 has 2 divisors, whose sum is σ = 211133422223082. Its totient is φ = 211133422223080.

The previous prime is 211133422222951. The next prime is 211133422223089. The reversal of 211133422223081 is 180322224331112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 210292313128681 + 841109094400 = 14501459^2 + 917120^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211133422223081 is a prime.

It is a super-2 number, since 2×2111334222230812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211133422223089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105566711111540 + 105566711111541.

It is an arithmetic number, because the mean of its divisors is an integer number (105566711111541).

Almost surely, 2211133422223081 is an apocalyptic number.

It is an amenable number.

211133422223081 is a deficient number, since it is larger than the sum of its proper divisors (1).

211133422223081 is an equidigital number, since it uses as much as digits as its factorization.

211133422223081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 35.

Adding to 211133422223081 its reverse (180322224331112), we get a palindrome (391455646554193).

The spelling of 211133422223081 in words is "two hundred eleven trillion, one hundred thirty-three billion, four hundred twenty-two million, two hundred twenty-three thousand, eighty-one".