Base | Representation |
---|---|
bin | 1100010010100010010… |
… | …0110011100010000001 |
3 | 202011222022010022112121 |
4 | 3010220210303202001 |
5 | 11424400314300101 |
6 | 240554345124241 |
7 | 21153046350151 |
oct | 3045044634201 |
9 | 664868108477 |
10 | 211134134401 |
11 | 815a5795173 |
12 | 34b04489681 |
13 | 16ba9c7c098 |
14 | a30cb0a761 |
15 | 575abac0a1 |
hex | 3128933881 |
211134134401 has 2 divisors, whose sum is σ = 211134134402. Its totient is φ = 211134134400.
The previous prime is 211134134383. The next prime is 211134134411. The reversal of 211134134401 is 104431431112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 178400640625 + 32733493776 = 422375^2 + 180924^2 .
It is a cyclic number.
It is not a de Polignac number, because 211134134401 - 225 = 211100579969 is a prime.
It is not a weakly prime, because it can be changed into another prime (211134134411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105567067200 + 105567067201.
It is an arithmetic number, because the mean of its divisors is an integer number (105567067201).
Almost surely, 2211134134401 is an apocalyptic number.
It is an amenable number.
211134134401 is a deficient number, since it is larger than the sum of its proper divisors (1).
211134134401 is an equidigital number, since it uses as much as digits as its factorization.
211134134401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 211134134401 its reverse (104431431112), we get a palindrome (315565565513).
It can be divided in two parts, 21113 and 4134401, that added together give a palindrome (4155514).
The spelling of 211134134401 in words is "two hundred eleven billion, one hundred thirty-four million, one hundred thirty-four thousand, four hundred one".
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