Base | Representation |
---|---|
bin | 10011101010011111… |
… | …111001101001100001 |
3 | 2000111110220102120121 |
4 | 103222133321221201 |
5 | 321220202202241 |
6 | 13411044240241 |
7 | 1345140614536 |
oct | 235237715141 |
9 | 60443812517 |
10 | 21114100321 |
11 | 8a553a5096 |
12 | 41130a0081 |
13 | 1cb64545b2 |
14 | 1044254d8d |
15 | 838989ad1 |
hex | 4ea7f9a61 |
21114100321 has 2 divisors, whose sum is σ = 21114100322. Its totient is φ = 21114100320.
The previous prime is 21114100237. The next prime is 21114100361. The reversal of 21114100321 is 12300141112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14033719296 + 7080381025 = 118464^2 + 84145^2 .
It is a cyclic number.
It is not a de Polignac number, because 21114100321 - 215 = 21114067553 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21114100295 and 21114100304.
It is not a weakly prime, because it can be changed into another prime (21114100361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10557050160 + 10557050161.
It is an arithmetic number, because the mean of its divisors is an integer number (10557050161).
Almost surely, 221114100321 is an apocalyptic number.
It is an amenable number.
21114100321 is a deficient number, since it is larger than the sum of its proper divisors (1).
21114100321 is an equidigital number, since it uses as much as digits as its factorization.
21114100321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 21114100321 its reverse (12300141112), we get a palindrome (33414241433).
The spelling of 21114100321 in words is "twenty-one billion, one hundred fourteen million, one hundred thousand, three hundred twenty-one".
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