Base | Representation |
---|---|
bin | 1100010010100011111… |
… | …1110011101101001001 |
3 | 202011222210102221112222 |
4 | 3010220333303231021 |
5 | 11424404122304001 |
6 | 240555200543425 |
7 | 21153163461365 |
oct | 3045077635511 |
9 | 664883387488 |
10 | 211141213001 |
11 | 815a978a454 |
12 | 34b06921b75 |
13 | 16bab589cc4 |
14 | a30da302a5 |
15 | 575b60961b |
hex | 3128ff3b49 |
211141213001 has 16 divisors (see below), whose sum is σ = 231434380800. Its totient is φ = 191759581440.
The previous prime is 211141212983. The next prime is 211141213051. The reversal of 211141213001 is 100312141112.
It is a cyclic number.
It is not a de Polignac number, because 211141213001 - 234 = 193961343817 is a prime.
It is a super-2 number, since 2×2111412130012 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211141213051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 390071 + ... + 757916.
It is an arithmetic number, because the mean of its divisors is an integer number (14464648800).
Almost surely, 2211141213001 is an apocalyptic number.
It is an amenable number.
211141213001 is a deficient number, since it is larger than the sum of its proper divisors (20293167799).
211141213001 is a wasteful number, since it uses less digits than its factorization.
211141213001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1148384.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 211141213001 its reverse (100312141112), we get a palindrome (311453354113).
The spelling of 211141213001 in words is "two hundred eleven billion, one hundred forty-one million, two hundred thirteen thousand, one".
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