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211141213001 = 17313491147987
BaseRepresentation
bin1100010010100011111…
…1110011101101001001
3202011222210102221112222
43010220333303231021
511424404122304001
6240555200543425
721153163461365
oct3045077635511
9664883387488
10211141213001
11815a978a454
1234b06921b75
1316bab589cc4
14a30da302a5
15575b60961b
hex3128ff3b49

211141213001 has 16 divisors (see below), whose sum is σ = 231434380800. Its totient is φ = 191759581440.

The previous prime is 211141212983. The next prime is 211141213051. The reversal of 211141213001 is 100312141112.

It is a cyclic number.

It is not a de Polignac number, because 211141213001 - 234 = 193961343817 is a prime.

It is a super-2 number, since 2×2111412130012 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211141213051) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 390071 + ... + 757916.

It is an arithmetic number, because the mean of its divisors is an integer number (14464648800).

Almost surely, 2211141213001 is an apocalyptic number.

It is an amenable number.

211141213001 is a deficient number, since it is larger than the sum of its proper divisors (20293167799).

211141213001 is a wasteful number, since it uses less digits than its factorization.

211141213001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1148384.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 211141213001 its reverse (100312141112), we get a palindrome (311453354113).

The spelling of 211141213001 in words is "two hundred eleven billion, one hundred forty-one million, two hundred thirteen thousand, one".

Divisors: 1 17 31 349 527 5933 10819 183923 1147987 19515779 35587597 400647463 604989149 6811006871 12420071353 211141213001