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2111412130431 = 312593529158407
BaseRepresentation
bin11110101110011001111…
…110000101001001111111
321110211220221102111010020
4132232121332011021333
5234043133001133211
64253545213343223
7305354521662612
oct36563176051177
97424827374106
102111412130431
1174449911543a
122a1257797b13
1312414a4991c6
147429b422179
1539dc9064306
hex1eb99f8527f

2111412130431 has 16 divisors (see below), whose sum is σ = 2818268409600. Its totient is φ = 1406082621888.

The previous prime is 2111412130411. The next prime is 2111412130433. The reversal of 2111412130431 is 1340312141112.

It is not a de Polignac number, because 2111412130431 - 29 = 2111412129919 is a prime.

It is a super-2 number, since 2×21114121304312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111412130433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13249830 + ... + 13408236.

It is an arithmetic number, because the mean of its divisors is an integer number (176141775600).

Almost surely, 22111412130431 is an apocalyptic number.

2111412130431 is a deficient number, since it is larger than the sum of its proper divisors (706856279169).

2111412130431 is a wasteful number, since it uses less digits than its factorization.

2111412130431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163198.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 2111412130431 its reverse (1340312141112), we get a palindrome (3451724271543).

The spelling of 2111412130431 in words is "two trillion, one hundred eleven billion, four hundred twelve million, one hundred thirty thousand, four hundred thirty-one".

Divisors: 1 3 1259 3529 3777 10587 158407 475221 4443011 13329033 199434413 559018303 598303239 1677054909 703804043477 2111412130431