2111412141001 has 2 divisors, whose sum is σ = 2111412141002. Its totient is φ = 2111412141000.

The previous prime is 2111412140993. The next prime is 2111412141161. The reversal of 2111412141001 is 1001412141112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2046547691776 + 64864449225 = 1430576^2 + 254685^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111412141001 - 2³ = 2111412140993 is a prime.

It is a super-2 number, since 2×2111412141001² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2111412141001.

It is not a weakly prime, because it can be changed into another prime (2111412141701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055706070500 + 1055706070501.

It is an arithmetic number, because the mean of its divisors is an integer number (1055706070501).

Almost surely, 2^{2111412141001} is an apocalyptic number.

It is an amenable number.

2111412141001 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111412141001 is an equidigital number, since it uses as much as digits as its factorization.

2111412141001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 2111412141001 its reverse (1001412141112), we get a palindrome (3112824282113).

The spelling of 2111412141001 in words is "two trillion, one hundred eleven billion, four hundred twelve million, one hundred forty-one thousand, one".