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2111414042113 is a prime number
BaseRepresentation
bin11110101110011010000…
…101010111111000000001
321110211221002000121110021
4132232122011113320001
5234043133443321423
64253545322333441
7305354544144205
oct36563205277001
97424832017407
102111414042113
1174449a200742
122a125835a281
1312414a9b838c
147429b79cb05
1539dc92e095d
hex1eb9a157e01

2111414042113 has 2 divisors, whose sum is σ = 2111414042114. Its totient is φ = 2111414042112.

The previous prime is 2111414042099. The next prime is 2111414042123. The reversal of 2111414042113 is 3112404141112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1573900720704 + 537513321409 = 1254552^2 + 733153^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111414042113 - 29 = 2111414041601 is a prime.

It is not a weakly prime, because it can be changed into another prime (2111414042123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055707021056 + 1055707021057.

It is an arithmetic number, because the mean of its divisors is an integer number (1055707021057).

Almost surely, 22111414042113 is an apocalyptic number.

It is an amenable number.

2111414042113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111414042113 is an equidigital number, since it uses as much as digits as its factorization.

2111414042113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 2111414042113 its reverse (3112404141112), we get a palindrome (5223818183225).

The spelling of 2111414042113 in words is "two trillion, one hundred eleven billion, four hundred fourteen million, forty-two thousand, one hundred thirteen".