21114201403 has 2 divisors, whose sum is σ = 21114201404. Its totient is φ = 21114201402.

The previous prime is 21114201397. The next prime is 21114201481. The reversal of 21114201403 is 30410241112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21114201403 - 2⁵ = 21114201371 is a prime.

It is a super-4 number, since 4×21114201403⁴ (a number of 42 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (21114205403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10557100701 + 10557100702.

It is an arithmetic number, because the mean of its divisors is an integer number (10557100702).

Almost surely, 2^21114201403 is an apocalyptic number.

21114201403 is a deficient number, since it is larger than the sum of its proper divisors (1).

21114201403 is an equidigital number, since it uses as much as digits as its factorization.

21114201403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 21114201403 its reverse (30410241112), we get a palindrome (51524442515).

The spelling of 21114201403 in words is "twenty-one billion, one hundred fourteen million, two hundred one thousand, four hundred three".