211142414113 has 2 divisors, whose sum is σ = 211142414114. Its totient is φ = 211142414112.

The previous prime is 211142414069. The next prime is 211142414123. The reversal of 211142414113 is 311414241112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 208111140864 + 3031273249 = 456192^2 + 55057^2 .

It is a cyclic number.

It is not a de Polignac number, because 211142414113 - 2²⁵ = 211108859681 is a prime.

It is a super-2 number, since 2×211142414113² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211142414123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105571207056 + 105571207057.

It is an arithmetic number, because the mean of its divisors is an integer number (105571207057).

Almost surely, 2^211142414113 is an apocalyptic number.

It is an amenable number.

211142414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211142414113 is an equidigital number, since it uses as much as digits as its factorization.

211142414113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 768, while the sum is 25.

Adding to 211142414113 its reverse (311414241112), we get a palindrome (522556655225).

The spelling of 211142414113 in words is "two hundred eleven billion, one hundred forty-two million, four hundred fourteen thousand, one hundred thirteen".