Base | Representation |
---|---|
bin | 1001100110101011000100… |
… | …00110010100111000000001 |
3 | 2202210001102010002120000211 |
4 | 10303111202012110320001 |
5 | 10232012230001114334 |
6 | 112530221041314121 |
7 | 4306604201065354 |
oct | 463254206247001 |
9 | 82701363076024 |
10 | 21120000019969 |
11 | 6802a3a461054 |
12 | 2451245335941 |
13 | ba27b8772a46 |
14 | 5302dba1429b |
15 | 2695a65a8a64 |
hex | 133562194e01 |
21120000019969 has 2 divisors, whose sum is σ = 21120000019970. Its totient is φ = 21120000019968.
The previous prime is 21120000019931. The next prime is 21120000020017. The reversal of 21120000019969 is 96991000002112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11566256846400 + 9553743173569 = 3400920^2 + 3090913^2 .
It is a cyclic number.
It is not a de Polignac number, because 21120000019969 - 213 = 21120000011777 is a prime.
It is a super-2 number, since 2×211200000199692 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21120000019669) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560000009984 + 10560000009985.
It is an arithmetic number, because the mean of its divisors is an integer number (10560000009985).
Almost surely, 221120000019969 is an apocalyptic number.
It is an amenable number.
21120000019969 is a deficient number, since it is larger than the sum of its proper divisors (1).
21120000019969 is an equidigital number, since it uses as much as digits as its factorization.
21120000019969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 40.
The spelling of 21120000019969 in words is "twenty-one trillion, one hundred twenty billion, nineteen thousand, nine hundred sixty-nine".
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