Base | Representation |
---|---|
bin | 1001100110101011000110… |
… | …10010100011000101101011 |
3 | 2202210001110111200201000212 |
4 | 10303111203102203011223 |
5 | 10232012300110014011 |
6 | 112530223033451335 |
7 | 4306604532655442 |
oct | 463254322430553 |
9 | 82701414621025 |
10 | 21120020001131 |
11 | 6802a4a769207 |
12 | 245124bb70b4b |
13 | ba27bc94a70c |
14 | 530300535d59 |
15 | 2695a820408b |
hex | 1335634a316b |
21120020001131 has 2 divisors, whose sum is σ = 21120020001132. Its totient is φ = 21120020001130.
The previous prime is 21120020001109. The next prime is 21120020001221. The reversal of 21120020001131 is 13110002002112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21120020001131 - 214 = 21120019984747 is a prime.
It is a super-3 number, since 3×211200200011313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (21120020501131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560010000565 + 10560010000566.
It is an arithmetic number, because the mean of its divisors is an integer number (10560010000566).
Almost surely, 221120020001131 is an apocalyptic number.
21120020001131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21120020001131 is an equidigital number, since it uses as much as digits as its factorization.
21120020001131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 21120020001131 its reverse (13110002002112), we get a palindrome (34230022003243).
The spelling of 21120020001131 in words is "twenty-one trillion, one hundred twenty billion, twenty million, one thousand, one hundred thirty-one".
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