Base | Representation |
---|---|
bin | 11110101110111101001… |
… | …100011101111001001011 |
3 | 21110220110010110001220110 |
4 | 132232331030131321023 |
5 | 234100340243314311 |
6 | 4254124004125403 |
7 | 305405256116601 |
oct | 36567514357113 |
9 | 7426403401813 |
10 | 2112003104331 |
11 | 74477176891a |
12 | 2a13a1696863 |
13 | 124212a545c3 |
14 | 74315ad9871 |
15 | 39e10d9c8a6 |
hex | 1ebbd31de4b |
2112003104331 has 32 divisors (see below), whose sum is σ = 2867423516928. Its totient is φ = 1382434099200.
The previous prime is 2112003104293. The next prime is 2112003104353. The reversal of 2112003104331 is 1334013002112.
It is not a de Polignac number, because 2112003104331 - 27 = 2112003104203 is a prime.
It is a super-2 number, since 2×21120031043312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112003104298 and 2112003104307.
It is not an unprimeable number, because it can be changed into a prime (2112003108331) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 198734040 + ... + 198744666.
It is an arithmetic number, because the mean of its divisors is an integer number (89606984904).
Almost surely, 22112003104331 is an apocalyptic number.
2112003104331 is a deficient number, since it is larger than the sum of its proper divisors (755420412597).
2112003104331 is a wasteful number, since it uses less digits than its factorization.
2112003104331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13851.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 2112003104331 its reverse (1334013002112), we get a palindrome (3446016106443).
The spelling of 2112003104331 in words is "two trillion, one hundred twelve billion, three million, one hundred four thousand, three hundred thirty-one".
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