Base | Representation |
---|---|
bin | 11110101110111101110… |
… | …000010000011100000001 |
3 | 21110220110210002201200112 |
4 | 132232331300100130001 |
5 | 234100400144031101 |
6 | 4254124541201105 |
7 | 305405431633556 |
oct | 36567560203401 |
9 | 7426423081615 |
10 | 2112012486401 |
11 | 744776a967a4 |
12 | 2a13a4860195 |
13 | 12421498ab1c |
14 | 7431705ca2d |
15 | 39e11b026bb |
hex | 1ebbdc10701 |
2112012486401 has 2 divisors, whose sum is σ = 2112012486402. Its totient is φ = 2112012486400.
The previous prime is 2112012486383. The next prime is 2112012486583. The reversal of 2112012486401 is 1046842102112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1129971126001 + 982041360400 = 1063001^2 + 990980^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112012486401 - 214 = 2112012470017 is a prime.
It is not a weakly prime, because it can be changed into another prime (2112012486601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056006243200 + 1056006243201.
It is an arithmetic number, because the mean of its divisors is an integer number (1056006243201).
Almost surely, 22112012486401 is an apocalyptic number.
It is an amenable number.
2112012486401 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112012486401 is an equidigital number, since it uses as much as digits as its factorization.
2112012486401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 32.
Adding to 2112012486401 its reverse (1046842102112), we get a palindrome (3158854588513).
The spelling of 2112012486401 in words is "two trillion, one hundred twelve billion, twelve million, four hundred eighty-six thousand, four hundred one".
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