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211210011113 is a prime number
BaseRepresentation
bin1100010010110100011…
…0010000000111101001
3202012011120220020211012
43010231012100013221
511430024230323423
6241010055313305
721154660321103
oct3045506200751
9665146806735
10211210011113
11816345aa4a2
1234b2597b835
1316bbc8c774a
14a318c1c573
155762699078
hex312d1901e9

211210011113 has 2 divisors, whose sum is σ = 211210011114. Its totient is φ = 211210011112.

The previous prime is 211210011013. The next prime is 211210011121. The reversal of 211210011113 is 311110012112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123255059929 + 87954951184 = 351077^2 + 296572^2 .

It is a cyclic number.

It is not a de Polignac number, because 211210011113 - 28 = 211210010857 is a prime.

It is not a weakly prime, because it can be changed into another prime (211210011013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605005556 + 105605005557.

It is an arithmetic number, because the mean of its divisors is an integer number (105605005557).

Almost surely, 2211210011113 is an apocalyptic number.

It is an amenable number.

211210011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211210011113 is an equidigital number, since it uses as much as digits as its factorization.

211210011113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 211210011113 its reverse (311110012112), we get a palindrome (522320023225).

Subtracting 211210011113 from its reverse (311110012112), we obtain a palindrome (99900000999).

The spelling of 211210011113 in words is "two hundred eleven billion, two hundred ten million, eleven thousand, one hundred thirteen".