Base | Representation |
---|---|
bin | 110000000001100000110101… |
… | …000000001110100011101011 |
3 | 1000200211111110001112220220101 |
4 | 300001200311000032203223 |
5 | 210140431442424001141 |
6 | 2025112343222010231 |
7 | 62326301450521342 |
oct | 6001406500164353 |
9 | 1020744401486811 |
10 | 211210201000171 |
11 | 6133081a25390a |
12 | 1b831b50b76977 |
13 | 90b1062236b79 |
14 | 3a228b1da2b59 |
15 | 19640de531531 |
hex | c0183500e8eb |
211210201000171 has 2 divisors, whose sum is σ = 211210201000172. Its totient is φ = 211210201000170.
The previous prime is 211210201000129. The next prime is 211210201000237. The reversal of 211210201000171 is 171000102012112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211210201000171 - 221 = 211210198903019 is a prime.
It is not a weakly prime, because it can be changed into another prime (211210201090171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605100500085 + 105605100500086.
It is an arithmetic number, because the mean of its divisors is an integer number (105605100500086).
Almost surely, 2211210201000171 is an apocalyptic number.
211210201000171 is a deficient number, since it is larger than the sum of its proper divisors (1).
211210201000171 is an equidigital number, since it uses as much as digits as its factorization.
211210201000171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 211210201000171 its reverse (171000102012112), we get a palindrome (382210303012283).
The spelling of 211210201000171 in words is "two hundred eleven trillion, two hundred ten billion, two hundred one million, one hundred seventy-one", and thus it is an aban number.
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