2112102034041 has 4 divisors (see below), whose sum is σ = 2816136045392. Its totient is φ = 1408068022692.

The previous prime is 2112102034013. The next prime is 2112102034043. The reversal of 2112102034041 is 1404302012112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2112102034041 - 2¹¹ = 2112102031993 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2112102033999 and 2112102034017.

It is not an unprimeable number, because it can be changed into a prime (2112102034043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352017005671 + ... + 352017005676.

It is an arithmetic number, because the mean of its divisors is an integer number (704034011348).

Almost surely, 2^{2112102034041} is an apocalyptic number.

It is an amenable number.

2112102034041 is a deficient number, since it is larger than the sum of its proper divisors (704034011351).

2112102034041 is an equidigital number, since it uses as much as digits as its factorization.

2112102034041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 704034011350.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 2112102034041 its reverse (1404302012112), we get a palindrome (3516404046153).

The spelling of 2112102034041 in words is "two trillion, one hundred twelve billion, one hundred two million, thirty-four thousand, forty-one".