Base | Representation |
---|---|
bin | 110000000001100000110101… |
… | …100110011010111000001011 |
3 | 1000200211111110202101120200211 |
4 | 300001200311212122320023 |
5 | 210140432003004341412 |
6 | 2025112344220341551 |
7 | 62326301631600556 |
oct | 6001406546327013 |
9 | 1020744422346624 |
10 | 211210211012107 |
11 | 61330824971a3a |
12 | 1b831b543a48b7 |
13 | 90b1064330ca8 |
14 | 3a228b344b69d |
15 | 19640e035cca7 |
hex | c0183599ae0b |
211210211012107 has 2 divisors, whose sum is σ = 211210211012108. Its totient is φ = 211210211012106.
The previous prime is 211210211012089. The next prime is 211210211012117. The reversal of 211210211012107 is 701210112012112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211210211012107 - 211 = 211210211010059 is a prime.
It is not a weakly prime, because it can be changed into another prime (211210211012117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605105506053 + 105605105506054.
It is an arithmetic number, because the mean of its divisors is an integer number (105605105506054).
Almost surely, 2211210211012107 is an apocalyptic number.
211210211012107 is a deficient number, since it is larger than the sum of its proper divisors (1).
211210211012107 is an equidigital number, since it uses as much as digits as its factorization.
211210211012107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 211210211012107 its reverse (701210112012112), we get a palindrome (912420323024219).
The spelling of 211210211012107 in words is "two hundred eleven trillion, two hundred ten billion, two hundred eleven million, twelve thousand, one hundred seven".
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