Base | Representation |
---|---|
bin | 1100010010110100101… |
… | …0001001111000010010 |
3 | 202012011122211020010201 |
4 | 3010231022021320102 |
5 | 11430030011043010 |
6 | 241010133245414 |
7 | 21155002111465 |
oct | 3045512117022 |
9 | 665148736121 |
10 | 211211034130 |
11 | 81635139068 |
12 | 34b2619386a |
13 | 16bbcb95295 |
14 | a3190072dc |
15 | 57627ec23a |
hex | 312d289e12 |
211211034130 has 32 divisors (see below), whose sum is σ = 388493314560. Its totient is φ = 82639058880.
The previous prime is 211211034121. The next prime is 211211034157. The reversal of 211211034130 is 31430112112.
211211034130 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×2112110341302 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211211034098 and 211211034107.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 689211 + ... + 947329.
It is an arithmetic number, because the mean of its divisors is an integer number (12140416080).
Almost surely, 2211211034130 is an apocalyptic number.
211211034130 is a deficient number, since it is larger than the sum of its proper divisors (177282280430).
211211034130 is a wasteful number, since it uses less digits than its factorization.
211211034130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 259914.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 211211034130 its reverse (31430112112), we get a palindrome (242641146242).
The spelling of 211211034130 in words is "two hundred eleven billion, two hundred eleven million, thirty-four thousand, one hundred thirty".
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