2112111102121 has 8 divisors (see below), whose sum is σ = 2115420026184. Its totient is φ = 2108802407040.

The previous prime is 2112111102119. The next prime is 2112111102139. The reversal of 2112111102121 is 1212011112112.

It can be written as a sum of positive squares in 4 ways, for example, as 99086448400 + 2013024653721 = 314780^2 + 1418811^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2112111102121 - 2¹ = 2112111102119 is a prime.

It is a super-2 number, since 2×2112111102121² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2112111102095 and 2112111102104.

It is not an unprimeable number, because it can be changed into a prime (2112111702121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35635291 + ... + 35694511.

It is an arithmetic number, because the mean of its divisors is an integer number (264427503273).

Almost surely, 2^{2112111102121} is an apocalyptic number.

It is an amenable number.

2112111102121 is a deficient number, since it is larger than the sum of its proper divisors (3308924063).

2112111102121 is an equidigital number, since it uses as much as digits as its factorization.

2112111102121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114491.

The product of its (nonzero) digits is 16, while the sum is 16.

Adding to 2112111102121 its reverse (1212011112112), we get a palindrome (3324122214233).

Subtracting from 2112111102121 its reverse (1212011112112), we obtain a palindrome (900099990009).

The spelling of 2112111102121 in words is "two trillion, one hundred twelve billion, one hundred eleven million, one hundred two thousand, one hundred twenty-one".