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21121111112203 is a prime number
BaseRepresentation
bin1001100110101101001000…
…10100110011101000001011
32202210011021112210220001001
410303112210110303220023
510232022013421042303
6112530523212035431
74306643552160334
oct463264424635013
982704245726031
1021121111112203
11680345a6620a3
1224514b5462b77
13ba2934a0847b
145303a53dd28b
1526961ddd131d
hex1335a4533a0b

21121111112203 has 2 divisors, whose sum is σ = 21121111112204. Its totient is φ = 21121111112202.

The previous prime is 21121111112191. The next prime is 21121111112237. The reversal of 21121111112203 is 30221111112112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21121111112203 - 237 = 20983672158731 is a prime.

It is a super-2 number, since 2×211211111122032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21121111112243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560555556101 + 10560555556102.

It is an arithmetic number, because the mean of its divisors is an integer number (10560555556102).

Almost surely, 221121111112203 is an apocalyptic number.

21121111112203 is a deficient number, since it is larger than the sum of its proper divisors (1).

21121111112203 is an equidigital number, since it uses as much as digits as its factorization.

21121111112203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 21121111112203 its reverse (30221111112112), we get a palindrome (51342222224315).

Subtracting 21121111112203 from its reverse (30221111112112), we obtain a palindrome (9099999999909).

The spelling of 21121111112203 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred eleven million, one hundred twelve thousand, two hundred three".