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21121120111097 is a prime number
BaseRepresentation
bin1001100110101101001001…
…10111001000100111111001
32202210011022011202002012102
410303112210313020213321
510232022023222023342
6112530524132553145
74306644021520226
oct463264467104771
982704264662172
1021121120111097
1168034647490a6
1224514b84827b5
13ba2936839466
145303a66a294d
1526961eaac832
hex1335a4dc89f9

21121120111097 has 2 divisors, whose sum is σ = 21121120111098. Its totient is φ = 21121120111096.

The previous prime is 21121120111061. The next prime is 21121120111103. The reversal of 21121120111097 is 79011102112112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11133093083641 + 9988027027456 = 3336629^2 + 3160384^2 .

It is a cyclic number.

It is not a de Polignac number, because 21121120111097 - 214 = 21121120094713 is a prime.

It is a super-3 number, since 3×211211201110973 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (21121120101097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560560055548 + 10560560055549.

It is an arithmetic number, because the mean of its divisors is an integer number (10560560055549).

Almost surely, 221121120111097 is an apocalyptic number.

It is an amenable number.

21121120111097 is a deficient number, since it is larger than the sum of its proper divisors (1).

21121120111097 is an equidigital number, since it uses as much as digits as its factorization.

21121120111097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 29.

The spelling of 21121120111097 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred twenty million, one hundred eleven thousand, ninety-seven".