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2112113137 is a prime number
BaseRepresentation
bin111110111100100…
…0100100111110001
312110012022110112111
41331321010213301
513311200110022
6545325525321
7103224444151
oct17571044761
95405273474
102112113137
11994261952
124ab413841
1327876c4b4
14160720761
15c565b477
hex7de449f1

2112113137 has 2 divisors, whose sum is σ = 2112113138. Its totient is φ = 2112113136.

The previous prime is 2112113083. The next prime is 2112113147. The reversal of 2112113137 is 7313112112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2111953936 + 159201 = 45956^2 + 399^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112113137 - 27 = 2112113009 is a prime.

It is a super-2 number, since 2×21121131372 = 8922043806975961538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2112113147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056056568 + 1056056569.

It is an arithmetic number, because the mean of its divisors is an integer number (1056056569).

Almost surely, 22112113137 is an apocalyptic number.

It is an amenable number.

2112113137 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112113137 is an equidigital number, since it uses as much as digits as its factorization.

2112113137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 252, while the sum is 22.

The square root of 2112113137 is about 45957.7320698052. The cubic root of 2112113137 is about 1283.0366413627.

Adding to 2112113137 its reverse (7313112112), we get a palindrome (9425225249).

The spelling of 2112113137 in words is "two billion, one hundred twelve million, one hundred thirteen thousand, one hundred thirty-seven".