Base | Representation |
---|---|
bin | 1100010010110100111… |
… | …0101001011110100011 |
3 | 202012011202001002001101 |
4 | 3010231032221132203 |
5 | 11430030311242011 |
6 | 241010214415231 |
7 | 21155015116054 |
oct | 3045516513643 |
9 | 665152032041 |
10 | 211212212131 |
11 | 81635873118 |
12 | 34b26661517 |
13 | 16bc01b851b |
14 | a31923272b |
15 | 57629812c1 |
hex | 312d3a97a3 |
211212212131 has 2 divisors, whose sum is σ = 211212212132. Its totient is φ = 211212212130.
The previous prime is 211212212089. The next prime is 211212212137. The reversal of 211212212131 is 131212212112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211212212131 is a prime.
It is a super-2 number, since 2×2112122121312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211212212099 and 211212212108.
It is not a weakly prime, because it can be changed into another prime (211212212137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606106065 + 105606106066.
It is an arithmetic number, because the mean of its divisors is an integer number (105606106066).
Almost surely, 2211212212131 is an apocalyptic number.
211212212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
211212212131 is an equidigital number, since it uses as much as digits as its factorization.
211212212131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 96, while the sum is 19.
Subtracting from 211212212131 its sum of digits (19), we obtain a palindrome (211212212112).
Adding to 211212212131 its reverse (131212212112), we get a palindrome (342424424243).
The spelling of 211212212131 in words is "two hundred eleven billion, two hundred twelve million, two hundred twelve thousand, one hundred thirty-one".
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