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2112125666341 = 2943196331
BaseRepresentation
bin11110101111000100100…
…000000000010000100101
321110220202200001212101011
4132233010200000100211
5234101113132310331
64254144103102221
7305411304641335
oct36570440002045
97426680055334
102112125666341
1174482496a539
122a1416741971
131242322676c2
14743280c10c5
1539e1ba0c3b1
hex1ebc4800425

2112125666341 has 20 divisors (see below), whose sum is σ = 2258148467584. Its totient is φ = 1973489590800.

The previous prime is 2112125666323. The next prime is 2112125666347. The reversal of 2112125666341 is 1436665212112.

It is not a de Polignac number, because 2112125666341 - 215 = 2112125633573 is a prime.

It is a super-2 number, since 2×21121256663412 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2112125666294 and 2112125666303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2112125666347) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 21877546 + ... + 21973876.

Almost surely, 22112125666341 is an apocalyptic number.

It is an amenable number.

2112125666341 is a deficient number, since it is larger than the sum of its proper divisors (146022801243).

2112125666341 is an frugal number, since it uses more digits than its factorization.

2112125666341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96478 (or 96391 counting only the distinct ones).

The product of its digits is 103680, while the sum is 40.

The spelling of 2112125666341 in words is "two trillion, one hundred twelve billion, one hundred twenty-five million, six hundred sixty-six thousand, three hundred forty-one".

Divisors: 1 29 31 841 899 24389 26071 96331 707281 756059 2793599 2986261 21925711 81014371 86601569 2349416759 2511445501 68133086011 72831919529 2112125666341