Base | Representation |
---|---|
bin | 11110101111000100110… |
… | …100100000001111110001 |
3 | 21110220210001011212222111 |
4 | 132233010310200033301 |
5 | 234101121021241431 |
6 | 4254144414205321 |
7 | 305411401422565 |
oct | 36570464401761 |
9 | 7426701155874 |
10 | 2112131040241 |
11 | 7448279aaa82 |
12 | 2a14184b3841 |
13 | 1242333c9721 |
14 | 74328abd6a5 |
15 | 39e1c21e7b1 |
hex | 1ebc4d203f1 |
2112131040241 has 24 divisors (see below), whose sum is σ = 2174271019200. Its totient is φ = 2051654114400.
The previous prime is 2112131040209. The next prime is 2112131040247. The reversal of 2112131040241 is 1420401312112.
It is not a de Polignac number, because 2112131040241 - 25 = 2112131040209 is a prime.
It is a super-2 number, since 2×21121310402412 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2112131040247) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 661900956 + ... + 661904146.
It is an arithmetic number, because the mean of its divisors is an integer number (90594625800).
Almost surely, 22112131040241 is an apocalyptic number.
It is an amenable number.
2112131040241 is a deficient number, since it is larger than the sum of its proper divisors (62139978959).
2112131040241 is a wasteful number, since it uses less digits than its factorization.
2112131040241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5445 (or 5398 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 2112131040241 its reverse (1420401312112), we get a palindrome (3532532352353).
The spelling of 2112131040241 in words is "two trillion, one hundred twelve billion, one hundred thirty-one million, forty thousand, two hundred forty-one".
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