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21121314103 = 313534913931
BaseRepresentation
bin10011101010111011…
…011010110100110111
32000111222110221000201
4103222323122310313
5321224024022403
613411503021331
71345256131141
oct235273326467
960458427021
1021121314103
118a5948199a
12411559a847
131cb7aabbc6
1410451b1c91
1583941221d
hex4eaedad37

21121314103 has 16 divisors (see below), whose sum is σ = 21914514432. Its totient is φ = 20335392000.

The previous prime is 21121314101. The next prime is 21121314121. The reversal of 21121314103 is 30141312112.

It is a cyclic number.

It is not a de Polignac number, because 21121314103 - 21 = 21121314101 is a prime.

It is a super-2 number, since 2×211213141032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21121314101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5371048 + ... + 5374978.

It is an arithmetic number, because the mean of its divisors is an integer number (1369657152).

Almost surely, 221121314103 is an apocalyptic number.

21121314103 is a deficient number, since it is larger than the sum of its proper divisors (793200329).

21121314103 is a wasteful number, since it uses less digits than its factorization.

21121314103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4806.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 21121314103 its reverse (30141312112), we get a palindrome (51262626215).

The spelling of 21121314103 in words is "twenty-one billion, one hundred twenty-one million, three hundred fourteen thousand, one hundred three".

Divisors: 1 31 353 491 3931 10943 15221 121861 173323 1387643 1930121 5373013 43016933 59833751 681332713 21121314103