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2112132203171 is a prime number
BaseRepresentation
bin11110101111000100111…
…000111100001010100011
321110220210010100222012222
4132233010320330022203
5234101121321000141
64254144455141255
7305411414335214
oct36570470741243
97426703328188
102112132203171
11744828624781
122a141897482b
13124233715b53
1474328d0340b
1539e1c39e14b
hex1ebc4e3c2a3

2112132203171 has 2 divisors, whose sum is σ = 2112132203172. Its totient is φ = 2112132203170.

The previous prime is 2112132203117. The next prime is 2112132203179. The reversal of 2112132203171 is 1713022312112.

Together with previous prime (2112132203117) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2112132203171 is a prime.

It is a super-2 number, since 2×21121322031712 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2112132203171.

It is not a weakly prime, because it can be changed into another prime (2112132203179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056066101585 + 1056066101586.

It is an arithmetic number, because the mean of its divisors is an integer number (1056066101586).

Almost surely, 22112132203171 is an apocalyptic number.

2112132203171 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112132203171 is an equidigital number, since it uses as much as digits as its factorization.

2112132203171 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 2112132203171 its reverse (1713022312112), we get a palindrome (3825154515283).

The spelling of 2112132203171 in words is "two trillion, one hundred twelve billion, one hundred thirty-two million, two hundred three thousand, one hundred seventy-one".