Search a number
-
+
21121333355040 = 2535531875744263
BaseRepresentation
bin1001100110101101100011…
…00100100110001000100000
32202210011212000222222220020
410303112301210212020200
510232022442314330130
6112531001231313440
74306652221204542
oct463266144461040
982704760888806
1021121333355040
116803564057466
12245155797b880
13ba296ba7c9c9
145303c6b31692
15269633680e10
hex1335b1926220

21121333355040 has 192 divisors, whose sum is σ = 67792670136576. Its totient is φ = 5525665247232.

The previous prime is 21121333355033. The next prime is 21121333355053. The reversal of 21121333355040 is 4055333312112.

It is a super-2 number, since 2×211213333550402 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21121333354992 and 21121333355010.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 477155949 + ... + 477200211.

It is an arithmetic number, because the mean of its divisors is an integer number (353086823628).

Almost surely, 221121333355040 is an apocalyptic number.

21121333355040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21121333355040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (33896335068288).

21121333355040 is an abundant number, since it is smaller than the sum of its proper divisors (46671336781536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21121333355040 is a wasteful number, since it uses less digits than its factorization.

21121333355040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63091 (or 63083 counting only the distinct ones).

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 21121333355040 its reverse (4055333312112), we get a palindrome (25176666667152).

The spelling of 21121333355040 in words is "twenty-one trillion, one hundred twenty-one billion, three hundred thirty-three million, three hundred fifty-five thousand, forty".