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21121450315 = 578346715569
BaseRepresentation
bin10011101010111011…
…111100000101001011
32000111222201211212121
4103222323330011023
5321224042402230
613411505552111
71345260236230
oct235273740513
960458654777
1021121450315
118a59565269
124115645637
131cb7b28bc4
141045209787
1583943c77a
hex4eaefc14b

21121450315 has 32 divisors (see below), whose sum is σ = 29380216320. Its totient is φ = 14277225984.

The previous prime is 21121450289. The next prime is 21121450319. The reversal of 21121450315 is 51305412112.

It is not a de Polignac number, because 21121450315 - 25 = 21121450283 is a prime.

It is a super-2 number, since 2×211214503152 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21121450315.

It is not an unprimeable number, because it can be changed into a prime (21121450319) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1348851 + ... + 1364419.

It is an arithmetic number, because the mean of its divisors is an integer number (918131760).

Almost surely, 221121450315 is an apocalyptic number.

21121450315 is a deficient number, since it is larger than the sum of its proper divisors (8258766005).

21121450315 is a wasteful number, since it uses less digits than its factorization.

21121450315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16131.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 21121450315 its reverse (51305412112), we get a palindrome (72426862427).

The spelling of 21121450315 in words is "twenty-one billion, one hundred twenty-one million, four hundred fifty thousand, three hundred fifteen".

Divisors: 1 5 7 35 83 415 467 581 2335 2905 3269 15569 16345 38761 77845 108983 193805 271327 544915 1292227 1356635 6461135 7270723 9045589 36353615 45227945 50895061 254475305 603470009 3017350045 4224290063 21121450315