Base | Representation |
---|---|
bin | 1001100110101110110010… |
… | …10111100000000110110010 |
3 | 2202210020120120022102212021 |
4 | 10303113121113200012302 |
5 | 10232030324224323442 |
6 | 112531151401422054 |
7 | 4310004606165664 |
oct | 463273127400662 |
9 | 82706516272767 |
10 | 21122001011122 |
11 | 6803876a15350 |
12 | 245170349a92a |
13 | ba2a471a628b |
14 | 53044b68a534 |
15 | 2696720b4e67 |
hex | 1335d95e01b2 |
21122001011122 has 16 divisors (see below), whose sum is σ = 34585587720000. Its totient is φ = 9594711401040.
The previous prime is 21122001011099. The next prime is 21122001011197. The reversal of 21122001011122 is 22111010022112.
It is a super-2 number, since 2×211220010111222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21122001011096 and 21122001011105.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 309872622 + ... + 309940777.
It is an arithmetic number, because the mean of its divisors is an integer number (2161599232500).
Almost surely, 221122001011122 is an apocalyptic number.
21122001011122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
21122001011122 is a deficient number, since it is larger than the sum of its proper divisors (13463586708878).
21122001011122 is a wasteful number, since it uses less digits than its factorization.
21122001011122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 619814961.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 21122001011122 its reverse (22111010022112), we get a palindrome (43233011033234).
The spelling of 21122001011122 in words is "twenty-one trillion, one hundred twenty-two billion, one million, eleven thousand, one hundred twenty-two".
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