Base | Representation |
---|---|
bin | 11110101111001001000… |
… | …000111111010110100001 |
3 | 21110220221221121122221020 |
4 | 132233021000333112201 |
5 | 234101242031002431 |
6 | 4254155410520053 |
7 | 305413214600121 |
oct | 36571100772641 |
9 | 7426857548836 |
10 | 2112201422241 |
11 | 744863702019 |
12 | 2a1437b96029 |
13 | 124244b70091 |
14 | 743341a0c81 |
15 | 39e234c3696 |
hex | 1ebc903f5a1 |
2112201422241 has 8 divisors (see below), whose sum is σ = 2816443844640. Its totient is φ = 1408046640672.
The previous prime is 2112201422231. The next prime is 2112201422257. The reversal of 2112201422241 is 1422241022112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2112201422241 - 25 = 2112201422209 is a prime.
It is a super-2 number, since 2×21122014222412 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2112201422231) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21853951 + ... + 21950388.
It is an arithmetic number, because the mean of its divisors is an integer number (352055480580).
Almost surely, 22112201422241 is an apocalyptic number.
It is an amenable number.
2112201422241 is a deficient number, since it is larger than the sum of its proper divisors (704242422399).
2112201422241 is a wasteful number, since it uses less digits than its factorization.
2112201422241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43820415.
The product of its (nonzero) digits is 1024, while the sum is 24.
Adding to 2112201422241 its reverse (1422241022112), we get a palindrome (3534442444353).
The spelling of 2112201422241 in words is "two trillion, one hundred twelve billion, two hundred one million, four hundred twenty-two thousand, two hundred forty-one".
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