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21122022022113 = 37040674007371
BaseRepresentation
bin1001100110101110110101…
…00111101001101111100001
32202210020122000211220112010
410303113122213221233201
510232030400114201423
6112531153432023133
74310005252605345
oct463273247515741
982706560756463
1021122022022113
116803887866201
12245170a531aa9
13ba2a4b65190c
14530450399625
15269673d65693
hex1335da9e9be1

21122022022113 has 4 divisors (see below), whose sum is σ = 28162696029488. Its totient is φ = 14081348014740.

The previous prime is 21122022022063. The next prime is 21122022022121. The reversal of 21122022022113 is 31122022022112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21122022022113 - 213 = 21122022013921 is a prime.

It is a super-2 number, since 2×211220220221132 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21122022022113.

It is not an unprimeable number, because it can be changed into a prime (21122022029113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3520337003683 + ... + 3520337003688.

It is an arithmetic number, because the mean of its divisors is an integer number (7040674007372).

Almost surely, 221122022022113 is an apocalyptic number.

It is an amenable number.

21122022022113 is a deficient number, since it is larger than the sum of its proper divisors (7040674007375).

21122022022113 is an equidigital number, since it uses as much as digits as its factorization.

21122022022113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7040674007374.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 21122022022113 its reverse (31122022022112), we get a palindrome (52244044044225).

Subtracting 21122022022113 from its reverse (31122022022112), we obtain a palindrome (9999999999999).

The spelling of 21122022022113 in words is "twenty-one trillion, one hundred twenty-two billion, twenty-two million, twenty-two thousand, one hundred thirteen".

Divisors: 1 3 7040674007371 21122022022113