Base | Representation |
---|---|
bin | 110000000001101010111111… |
… | …010010100100111111011011 |
3 | 1000200212112121101122101120001 |
4 | 300001222333102210333123 |
5 | 210141121313404013201 |
6 | 2025121345553113431 |
7 | 62330136015144154 |
oct | 6001527722447733 |
9 | 1020775541571501 |
10 | 211221111001051 |
11 | 61335408700a68 |
12 | 1b834096858877 |
13 | 90b20b060caa8 |
14 | 3a23228d2692b |
15 | 196452c244301 |
hex | c01abf4a4fdb |
211221111001051 has 2 divisors, whose sum is σ = 211221111001052. Its totient is φ = 211221111001050.
The previous prime is 211221111000973. The next prime is 211221111001151. The reversal of 211221111001051 is 150100111122112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211221111001051 is a prime.
It is a super-2 number, since 2×2112211110010512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211221111001151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610555500525 + 105610555500526.
It is an arithmetic number, because the mean of its divisors is an integer number (105610555500526).
Almost surely, 2211221111001051 is an apocalyptic number.
211221111001051 is a deficient number, since it is larger than the sum of its proper divisors (1).
211221111001051 is an equidigital number, since it uses as much as digits as its factorization.
211221111001051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 19.
Adding to 211221111001051 its reverse (150100111122112), we get a palindrome (361321222123163).
The spelling of 211221111001051 in words is "two hundred eleven trillion, two hundred twenty-one billion, one hundred eleven million, one thousand, fifty-one".
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