Base | Representation |
---|---|
bin | 1001100110101111000000… |
… | …11101110100111111011011 |
3 | 2202210020212212102021212102 |
4 | 10303113200131310333123 |
5 | 10232031100222010133 |
6 | 112531211254234015 |
7 | 4310010553415111 |
oct | 463274035647733 |
9 | 82706785367772 |
10 | 21122120110043 |
11 | 6803928171107 |
12 | 245173735590b |
13 | ba2a65a76004 |
14 | 53045d40dab1 |
15 | 26967c78d7e8 |
hex | 1335e0774fdb |
21122120110043 has 2 divisors, whose sum is σ = 21122120110044. Its totient is φ = 21122120110042.
The previous prime is 21122120109947. The next prime is 21122120110073. The reversal of 21122120110043 is 34001102122112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21122120110043 - 210 = 21122120109019 is a prime.
It is a super-2 number, since 2×211221201100432 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21122120109997 and 21122120110024.
It is not a weakly prime, because it can be changed into another prime (21122120110073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561060055021 + 10561060055022.
It is an arithmetic number, because the mean of its divisors is an integer number (10561060055022).
Almost surely, 221122120110043 is an apocalyptic number.
21122120110043 is a deficient number, since it is larger than the sum of its proper divisors (1).
21122120110043 is an equidigital number, since it uses as much as digits as its factorization.
21122120110043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 21122120110043 its reverse (34001102122112), we get a palindrome (55123222232155).
The spelling of 21122120110043 in words is "twenty-one trillion, one hundred twenty-two billion, one hundred twenty million, one hundred ten thousand, forty-three".
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