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2112212102113 is a prime number
BaseRepresentation
bin11110101111001001101…
…001101110101111100001
321110220222200201020222001
4132233021221232233201
5234101302244231423
64254200431444001
7305413404430561
oct36571151565741
97426880636861
102112212102113
11744869736a63
122a143b686601
1312424713c229
1474335780da1
1539e243d2cad
hex1ebc9a6ebe1

2112212102113 has 2 divisors, whose sum is σ = 2112212102114. Its totient is φ = 2112212102112.

The previous prime is 2112212102107. The next prime is 2112212102123. The reversal of 2112212102113 is 3112012122112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2043618920704 + 68593181409 = 1429552^2 + 261903^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112212102113 - 213 = 2112212093921 is a prime.

It is a super-2 number, since 2×21122121021132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2112212102123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056106051056 + 1056106051057.

It is an arithmetic number, because the mean of its divisors is an integer number (1056106051057).

Almost surely, 22112212102113 is an apocalyptic number.

It is an amenable number.

2112212102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112212102113 is an equidigital number, since it uses as much as digits as its factorization.

2112212102113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 2112212102113 its reverse (3112012122112), we get a palindrome (5224224224225).

The spelling of 2112212102113 in words is "two trillion, one hundred twelve billion, two hundred twelve million, one hundred two thousand, one hundred thirteen".