Base | Representation |
---|---|
bin | 110000000001101011000101… |
… | …010100101010001110100011 |
3 | 1000200212112212110002100020201 |
4 | 300001223011110222032203 |
5 | 210141122020311210313 |
6 | 2025121404010250031 |
7 | 62330141354333215 |
oct | 6001530524521643 |
9 | 1020775773070221 |
10 | 211221212210083 |
11 | 6133545a848899 |
12 | 1b834104726917 |
13 | 90b20c85879aa |
14 | 3a232385505b5 |
15 | 19645360870dd |
hex | c01ac552a3a3 |
211221212210083 has 2 divisors, whose sum is σ = 211221212210084. Its totient is φ = 211221212210082.
The previous prime is 211221212210077. The next prime is 211221212210117. The reversal of 211221212210083 is 380012212122112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211221212210083 - 213 = 211221212201891 is a prime.
It is a super-2 number, since 2×2112212122100832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211221212210483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610606105041 + 105610606105042.
It is an arithmetic number, because the mean of its divisors is an integer number (105610606105042).
Almost surely, 2211221212210083 is an apocalyptic number.
211221212210083 is a deficient number, since it is larger than the sum of its proper divisors (1).
211221212210083 is an equidigital number, since it uses as much as digits as its factorization.
211221212210083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 28.
Adding to 211221212210083 its reverse (380012212122112), we get a palindrome (591233424332195).
The spelling of 211221212210083 in words is "two hundred eleven trillion, two hundred twenty-one billion, two hundred twelve million, two hundred ten thousand, eighty-three".
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