Base | Representation |
---|---|
bin | 1001100110101111000001… |
… | …00101011101110010000011 |
3 | 2202210020220000012000012211 |
4 | 10303113200211131302003 |
5 | 10232031101230042011 |
6 | 112531211405202551 |
7 | 4310010606424105 |
oct | 463274045356203 |
9 | 82706800160184 |
10 | 21122122112131 |
11 | 6803929309327 |
12 | 2451737b60457 |
13 | ba2a662c7391 |
14 | 53045d7b1575 |
15 | 26967ca36b21 |
hex | 1335e095dc83 |
21122122112131 has 2 divisors, whose sum is σ = 21122122112132. Its totient is φ = 21122122112130.
The previous prime is 21122122112087. The next prime is 21122122112159. The reversal of 21122122112131 is 13121122122112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21122122112131 - 29 = 21122122111619 is a prime.
It is a super-2 number, since 2×211221221121312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21122122115131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561061056065 + 10561061056066.
It is an arithmetic number, because the mean of its divisors is an integer number (10561061056066).
Almost surely, 221122122112131 is an apocalyptic number.
21122122112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21122122112131 is an equidigital number, since it uses as much as digits as its factorization.
21122122112131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 192, while the sum is 22.
Adding to 21122122112131 its reverse (13121122122112), we get a palindrome (34243244234243).
It can be divided in two parts, 21122122112 and 131, that multiplied together give a palindrome (2766997996672).
The spelling of 21122122112131 in words is "twenty-one trillion, one hundred twenty-two billion, one hundred twenty-two million, one hundred twelve thousand, one hundred thirty-one".
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