Base | Representation |
---|---|
bin | 110000000001101011001100… |
… | …010110011011000111101010 |
3 | 1000200212120011122221102122111 |
4 | 300001223030112123013222 |
5 | 210141122241002104002 |
6 | 2025121423421312534 |
7 | 62330144315441416 |
oct | 6001531426330752 |
9 | 1020776148842574 |
10 | 211221330113002 |
11 | 61335510358020 |
12 | 1b83413810574a |
13 | 90b2116b29231 |
14 | 3a2324a081d46 |
15 | 19645415c63d7 |
hex | c01acc59b1ea |
211221330113002 has 32 divisors (see below), whose sum is σ = 346994164915200. Its totient is φ = 95632294258800.
The previous prime is 211221330112937. The next prime is 211221330113071. The reversal of 211221330113002 is 200311033122112.
It is a super-3 number, since 3×2112213301130023 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20396949 + ... + 28956487.
It is an arithmetic number, because the mean of its divisors is an integer number (10843567653600).
Almost surely, 2211221330113002 is an apocalyptic number.
211221330113002 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
211221330113002 is a deficient number, since it is larger than the sum of its proper divisors (135772834802198).
211221330113002 is a wasteful number, since it uses less digits than its factorization.
211221330113002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8563962.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 211221330113002 its reverse (200311033122112), we get a palindrome (411532363235114).
The spelling of 211221330113002 in words is "two hundred eleven trillion, two hundred twenty-one billion, three hundred thirty million, one hundred thirteen thousand, two".
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