211222100000113 has 2 divisors, whose sum is σ = 211222100000114. Its totient is φ = 211222100000112.

The previous prime is 211222100000099. The next prime is 211222100000237. The reversal of 211222100000113 is 311000001222112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132083141664049 + 79138958336064 = 11492743^2 + 8896008^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211222100000113 is a prime.

It is a super-2 number, since 2×211222100000113² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211222100009113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611050000056 + 105611050000057.

It is an arithmetic number, because the mean of its divisors is an integer number (105611050000057).

Almost surely, 2^{211222100000113} is an apocalyptic number.

It is an amenable number.

211222100000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211222100000113 is an equidigital number, since it uses as much as digits as its factorization.

211222100000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 211222100000113 its reverse (311000001222112), we get a palindrome (522222101222225).

The spelling of 211222100000113 in words is "two hundred eleven trillion, two hundred twenty-two billion, one hundred million, one hundred thirteen", and thus it is an aban number.