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211223132011 is a prime number
BaseRepresentation
bin1100010010110111100…
…0010011011101101011
3202012012111120212022101
43010231320103131223
511430041110211021
6241011244434231
721155206666333
oct3045570233553
9665174525271
10211223132011
1181640a51411
1234b2a248977
1316bc253c9a8
14a31a8760c3
1557638dba91
hex312de1376b

211223132011 has 2 divisors, whose sum is σ = 211223132012. Its totient is φ = 211223132010.

The previous prime is 211223131997. The next prime is 211223132017. The reversal of 211223132011 is 110231322112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211223132011 - 213 = 211223123819 is a prime.

It is a super-2 number, since 2×2112231320112 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211223132011.

It is not a weakly prime, because it can be changed into another prime (211223132017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611566005 + 105611566006.

It is an arithmetic number, because the mean of its divisors is an integer number (105611566006).

Almost surely, 2211223132011 is an apocalyptic number.

211223132011 is a deficient number, since it is larger than the sum of its proper divisors (1).

211223132011 is an equidigital number, since it uses as much as digits as its factorization.

211223132011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 211223132011 its reverse (110231322112), we get a palindrome (321454454123).

The spelling of 211223132011 in words is "two hundred eleven billion, two hundred twenty-three million, one hundred thirty-two thousand, eleven".