Base | Representation |
---|---|
bin | 1100010010110111100… |
… | …0010011011101101011 |
3 | 202012012111120212022101 |
4 | 3010231320103131223 |
5 | 11430041110211021 |
6 | 241011244434231 |
7 | 21155206666333 |
oct | 3045570233553 |
9 | 665174525271 |
10 | 211223132011 |
11 | 81640a51411 |
12 | 34b2a248977 |
13 | 16bc253c9a8 |
14 | a31a8760c3 |
15 | 57638dba91 |
hex | 312de1376b |
211223132011 has 2 divisors, whose sum is σ = 211223132012. Its totient is φ = 211223132010.
The previous prime is 211223131997. The next prime is 211223132017. The reversal of 211223132011 is 110231322112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211223132011 - 213 = 211223123819 is a prime.
It is a super-2 number, since 2×2112231320112 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 211223132011.
It is not a weakly prime, because it can be changed into another prime (211223132017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611566005 + 105611566006.
It is an arithmetic number, because the mean of its divisors is an integer number (105611566006).
Almost surely, 2211223132011 is an apocalyptic number.
211223132011 is a deficient number, since it is larger than the sum of its proper divisors (1).
211223132011 is an equidigital number, since it uses as much as digits as its factorization.
211223132011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 211223132011 its reverse (110231322112), we get a palindrome (321454454123).
The spelling of 211223132011 in words is "two hundred eleven billion, two hundred twenty-three million, one hundred thirty-two thousand, eleven".
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