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21123131113 = 73017590159
BaseRepresentation
bin10011101011000010…
…010110011011101001
32000112002220020111101
4103223002112123221
5321230010143423
613412010001401
71345310436430
oct235302263351
960462806441
1021123131113
118a5a503057
124116116261
131cb8296c66
141045526117
158396707ad
hex4eb0966e9

21123131113 has 4 divisors (see below), whose sum is σ = 24140721280. Its totient is φ = 18105540948.

The previous prime is 21123131083. The next prime is 21123131147. The reversal of 21123131113 is 31113132112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21123131113 - 233 = 12533196521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21123131173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1508795073 + ... + 1508795086.

It is an arithmetic number, because the mean of its divisors is an integer number (6035180320).

Almost surely, 221123131113 is an apocalyptic number.

It is an amenable number.

21123131113 is a deficient number, since it is larger than the sum of its proper divisors (3017590167).

21123131113 is an equidigital number, since it uses as much as digits as its factorization.

21123131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3017590166.

The product of its digits is 108, while the sum is 19.

Adding to 21123131113 its reverse (31113132112), we get a palindrome (52236263225).

Subtracting 21123131113 from its reverse (31113132112), we obtain a palindrome (9990000999).

The spelling of 21123131113 in words is "twenty-one billion, one hundred twenty-three million, one hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 7 3017590159 21123131113