Base | Representation |
---|---|
bin | 11110101111010000001… |
… | …001001011100100011011 |
3 | 21110221021021122100102112 |
4 | 132233100021023210123 |
5 | 234102013134304242 |
6 | 4254215322022535 |
7 | 305416166223251 |
oct | 36572011134433 |
9 | 7427237570375 |
10 | 2112321009947 |
11 | 744915162035 |
12 | 2a1470047a4b |
13 | 124263881435 |
14 | 743460105d1 |
15 | 39e2dc46c82 |
hex | 1ebd024b91b |
2112321009947 has 2 divisors, whose sum is σ = 2112321009948. Its totient is φ = 2112321009946.
The previous prime is 2112321009889. The next prime is 2112321009983. The reversal of 2112321009947 is 7499001232112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112321009947 - 210 = 2112321008923 is a prime.
It is not a weakly prime, because it can be changed into another prime (2112321009247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056160504973 + 1056160504974.
It is an arithmetic number, because the mean of its divisors is an integer number (1056160504974).
Almost surely, 22112321009947 is an apocalyptic number.
2112321009947 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112321009947 is an equidigital number, since it uses as much as digits as its factorization.
2112321009947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 41.
The spelling of 2112321009947 in words is "two trillion, one hundred twelve billion, three hundred twenty-one million, nine thousand, nine hundred forty-seven".
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