2112412034131 has 4 divisors (see below), whose sum is σ = 2414185181872. Its totient is φ = 1810638886392.

The previous prime is 2112412034129. The next prime is 2112412034153. The reversal of 2112412034131 is 1314302142112.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2112412034131 - 2¹ = 2112412034129 is a prime.

It is a super-2 number, since 2×2112412034131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2112412034096 and 2112412034105.

It is not an unprimeable number, because it can be changed into a prime (2112410034131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150886573860 + ... + 150886573873.

It is an arithmetic number, because the mean of its divisors is an integer number (603546295468).

Almost surely, 2^{2112412034131} is an apocalyptic number.

2112412034131 is a deficient number, since it is larger than the sum of its proper divisors (301773147741).

2112412034131 is an equidigital number, since it uses as much as digits as its factorization.

2112412034131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 301773147740.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2112412034131 its reverse (1314302142112), we get a palindrome (3426714176243).

The spelling of 2112412034131 in words is "two trillion, one hundred twelve billion, four hundred twelve million, thirty-four thousand, one hundred thirty-one".