Base | Representation |
---|---|
bin | 110000000001111101111001… |
… | …110100111100001100010110 |
3 | 1000200221111000210102210201021 |
4 | 300001331321310330030112 |
5 | 210141434412113042332 |
6 | 2025134545134551354 |
7 | 62331455215423345 |
oct | 6001757164741426 |
9 | 1020844023383637 |
10 | 211241420440342 |
11 | 61342a8a871336 |
12 | 1b83800436855a |
13 | 90b3c9913baa6 |
14 | 3a241d435bb5c |
15 | 1964d1a235c97 |
hex | c01f79d3c316 |
211241420440342 has 16 divisors (see below), whose sum is σ = 316972357947072. Its totient is φ = 105583973833800.
The previous prime is 211241420440277. The next prime is 211241420440363. The reversal of 211241420440342 is 243044024142112.
211241420440342 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 211241420440298 and 211241420440307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 68697673 + ... + 71706715.
It is an arithmetic number, because the mean of its divisors is an integer number (19810772371692).
Almost surely, 2211241420440342 is an apocalyptic number.
211241420440342 is a deficient number, since it is larger than the sum of its proper divisors (105730937506730).
211241420440342 is a wasteful number, since it uses less digits than its factorization.
211241420440342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3021243.
The product of its (nonzero) digits is 49152, while the sum is 34.
Adding to 211241420440342 its reverse (243044024142112), we get a palindrome (454285444582454).
The spelling of 211241420440342 in words is "two hundred eleven trillion, two hundred forty-one billion, four hundred twenty million, four hundred forty thousand, three hundred forty-two".
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