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211242242113 = 730177463159
BaseRepresentation
bin1100010010111100000…
…1001101000001000001
3202012020211112202102221
43010233001031001001
511430111003221423
6241013210211041
721155531301040
oct3045701150101
9665224482387
10211242242113
1181650814091
1234b34723a81
1316bc64a1046
14a31d20c557
155765413e5d
hex312f04d041

211242242113 has 4 divisors (see below), whose sum is σ = 241419705280. Its totient is φ = 181064778948.

The previous prime is 211242242111. The next prime is 211242242129. The reversal of 211242242113 is 311242242112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211242242113 - 21 = 211242242111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211242242111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15088731573 + ... + 15088731586.

It is an arithmetic number, because the mean of its divisors is an integer number (60354926320).

Almost surely, 2211242242113 is an apocalyptic number.

It is an amenable number.

211242242113 is a deficient number, since it is larger than the sum of its proper divisors (30177463167).

211242242113 is an equidigital number, since it uses as much as digits as its factorization.

211242242113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30177463166.

The product of its digits is 1536, while the sum is 25.

Adding to 211242242113 its reverse (311242242112), we get a palindrome (522484484225).

Subtracting 211242242113 from its reverse (311242242112), we obtain a palindrome (99999999999).

The spelling of 211242242113 in words is "two hundred eleven billion, two hundred forty-two million, two hundred forty-two thousand, one hundred thirteen".

Divisors: 1 7 30177463159 211242242113