Base | Representation |
---|---|
bin | 1100010010111100100… |
… | …1000101111100111011 |
3 | 202012020222102211111121 |
4 | 3010233021011330323 |
5 | 11430112020412311 |
6 | 241013322410111 |
7 | 21155555003605 |
oct | 3045711057473 |
9 | 665228384447 |
10 | 211244310331 |
11 | 816519a6a5a |
12 | 34b35360937 |
13 | 16bc6a46542 |
14 | a31d5ca175 |
15 | 57656c1b71 |
hex | 312f245f3b |
211244310331 has 2 divisors, whose sum is σ = 211244310332. Its totient is φ = 211244310330.
The previous prime is 211244310293. The next prime is 211244310379. The reversal of 211244310331 is 133013442112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211244310331 - 227 = 211110092603 is a prime.
It is a super-2 number, since 2×2112443103312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211244310296 and 211244310305.
It is not a weakly prime, because it can be changed into another prime (211244310031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105622155165 + 105622155166.
It is an arithmetic number, because the mean of its divisors is an integer number (105622155166).
Almost surely, 2211244310331 is an apocalyptic number.
211244310331 is a deficient number, since it is larger than the sum of its proper divisors (1).
211244310331 is an equidigital number, since it uses as much as digits as its factorization.
211244310331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 211244310331 its reverse (133013442112), we get a palindrome (344257752443).
The spelling of 211244310331 in words is "two hundred eleven billion, two hundred forty-four million, three hundred ten thousand, three hundred thirty-one".
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