211264331400851 has 2 divisors, whose sum is σ = 211264331400852. Its totient is φ = 211264331400850.

The previous prime is 211264331400847. The next prime is 211264331400893. The reversal of 211264331400851 is 158004133462112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211264331400851 - 2² = 211264331400847 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211264331400799 and 211264331400808.

It is not a weakly prime, because it can be changed into another prime (211264331400251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105632165700425 + 105632165700426.

It is an arithmetic number, because the mean of its divisors is an integer number (105632165700426).

Almost surely, 2^{211264331400851} is an apocalyptic number.

211264331400851 is a deficient number, since it is larger than the sum of its proper divisors (1).

211264331400851 is an equidigital number, since it uses as much as digits as its factorization.

211264331400851 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 138240, while the sum is 41.

Adding to 211264331400851 its reverse (158004133462112), we get a palindrome (369268464862963).

The spelling of 211264331400851 in words is "two hundred eleven trillion, two hundred sixty-four billion, three hundred thirty-one million, four hundred thousand, eight hundred fifty-one".