Base | Representation |
---|---|
bin | 11110101111111000101… |
… | …011010001000110001011 |
3 | 21111000000200020011020010 |
4 | 132233320223101012023 |
5 | 234104411231042443 |
6 | 4254411013203003 |
7 | 305442064306110 |
oct | 36577053210613 |
9 | 7430020204203 |
10 | 2113001034123 |
11 | 745133aa8291 |
12 | 2a161b930463 |
13 | 1243417183c5 |
14 | 743ac468907 |
15 | 39e6d7c0733 |
hex | 1ebf8ad118b |
2113001034123 has 32 divisors (see below), whose sum is σ = 3227594388480. Its totient is φ = 1204511736960.
The previous prime is 2113001034121. The next prime is 2113001034127. The reversal of 2113001034123 is 3214301003112.
It is not a de Polignac number, because 2113001034123 - 21 = 2113001034121 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 2113001034123.
It is not an unprimeable number, because it can be changed into a prime (2113001034121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 42542538 + ... + 42592176.
It is an arithmetic number, because the mean of its divisors is an integer number (100862324640).
Almost surely, 22113001034123 is an apocalyptic number.
2113001034123 is a deficient number, since it is larger than the sum of its proper divisors (1114593354357).
2113001034123 is a wasteful number, since it uses less digits than its factorization.
2113001034123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54507.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 2113001034123 its reverse (3214301003112), we get a palindrome (5327302037235).
The spelling of 2113001034123 in words is "two trillion, one hundred thirteen billion, one million, thirty-four thousand, one hundred twenty-three".
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