Base | Representation |
---|---|
bin | 10011101011011100… |
… | …100110010111111001 |
3 | 2000112120211211111201 |
4 | 103223130212113321 |
5 | 321233240342103 |
6 | 13412413254201 |
7 | 1345423065655 |
oct | 235334462771 |
9 | 60476754451 |
10 | 21130012153 |
11 | 8a63382968 |
12 | 4118494361 |
13 | 1cb9835c93 |
14 | 10463d7a65 |
15 | 83a07e51d |
hex | 4eb7265f9 |
21130012153 has 2 divisors, whose sum is σ = 21130012154. Its totient is φ = 21130012152.
The previous prime is 21130012121. The next prime is 21130012187. The reversal of 21130012153 is 35121003112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19767516409 + 1362495744 = 140597^2 + 36912^2 .
It is a cyclic number.
It is not a de Polignac number, because 21130012153 - 25 = 21130012121 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21130012153.
It is not a weakly prime, because it can be changed into another prime (21130312153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565006076 + 10565006077.
It is an arithmetic number, because the mean of its divisors is an integer number (10565006077).
Almost surely, 221130012153 is an apocalyptic number.
It is an amenable number.
21130012153 is a deficient number, since it is larger than the sum of its proper divisors (1).
21130012153 is an equidigital number, since it uses as much as digits as its factorization.
21130012153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180, while the sum is 19.
Adding to 21130012153 its reverse (35121003112), we get a palindrome (56251015265).
The spelling of 21130012153 in words is "twenty-one billion, one hundred thirty million, twelve thousand, one hundred fifty-three".
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