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21130012153 is a prime number
BaseRepresentation
bin10011101011011100…
…100110010111111001
32000112120211211111201
4103223130212113321
5321233240342103
613412413254201
71345423065655
oct235334462771
960476754451
1021130012153
118a63382968
124118494361
131cb9835c93
1410463d7a65
1583a07e51d
hex4eb7265f9

21130012153 has 2 divisors, whose sum is σ = 21130012154. Its totient is φ = 21130012152.

The previous prime is 21130012121. The next prime is 21130012187. The reversal of 21130012153 is 35121003112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19767516409 + 1362495744 = 140597^2 + 36912^2 .

It is a cyclic number.

It is not a de Polignac number, because 21130012153 - 25 = 21130012121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21130012153.

It is not a weakly prime, because it can be changed into another prime (21130312153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565006076 + 10565006077.

It is an arithmetic number, because the mean of its divisors is an integer number (10565006077).

Almost surely, 221130012153 is an apocalyptic number.

It is an amenable number.

21130012153 is a deficient number, since it is larger than the sum of its proper divisors (1).

21130012153 is an equidigital number, since it uses as much as digits as its factorization.

21130012153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 21130012153 its reverse (35121003112), we get a palindrome (56251015265).

The spelling of 21130012153 in words is "twenty-one billion, one hundred thirty million, twelve thousand, one hundred fifty-three".