211300232113 has 4 divisors (see below), whose sum is σ = 211308322288. Its totient is φ = 211292141940.

The previous prime is 211300232083. The next prime is 211300232137. The reversal of 211300232113 is 311232003112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211300232113 - 2⁵ = 211300232081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211300232413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4005783 + ... + 4058188.

It is an arithmetic number, because the mean of its divisors is an integer number (52827080572).

Almost surely, 2^211300232113 is an apocalyptic number.

It is an amenable number.

211300232113 is a deficient number, since it is larger than the sum of its proper divisors (8090175).

211300232113 is an equidigital number, since it uses as much as digits as its factorization.

211300232113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8090174.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 211300232113 its reverse (311232003112), we get a palindrome (522532235225).

The spelling of 211300232113 in words is "two hundred eleven billion, three hundred million, two hundred thirty-two thousand, one hundred thirteen".